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Some Basic Concepts of Chemistry question

2024 · 27 Jan · Shift 1 · Q23
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Some Basic Concepts of Chemistry question

2024 · 27 Jan · Shift 1 · Q23

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
Mass of methane required to produce 22 g22 \mathrm{~g}22 g of CO2\mathrm{CO}_2CO2​ after complete combustion is ‾\underline{\hspace{2cm}}​ g. (Given Molar mass in g mol-1 C=12.0\mathrm{C}=12.0C=12.0, H=1.0\mathrm{H}=1.0H=1.0, O=16.0)\mathrm{O}=16.0)O=16.0)
Numerical answer
View written solutionFree

Correct answer: 8

  1. Write the balanced combustion reaction of methane
CH4+2O2→CO2+2H2O\mathrm{CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O}CH4​+2O2​→CO2​+2H2​O

From the balanced equation:

  • 111 mole of CH4\mathrm{CH_4}CH4​ produces 111 mole of CO2\mathrm{CO_2}CO2​.
  1. Find molar mass of CO2\mathrm{CO_2}CO2​
M(CO2)=12+2(16)=44 g mol−1M(\mathrm{CO_2}) = 12 + 2(16) = 44\ \mathrm{g\,mol^{-1}}M(CO2​)=12+2(16)=44 gmol−1
  1. Calculate moles of CO2\mathrm{CO_2}CO2​ formed

Given mass of CO2=22 g\mathrm{CO_2} = 22\ \mathrm{g}CO2​=22 g,

n(CO2)=2244=0.5 moln(\mathrm{CO_2}) = \frac{22}{44} = 0.5\ \mathrm{mol}n(CO2​)=4422​=0.5 mol
  1. Use stoichiometric ratio to find moles of methane required

Since 111 mole of CH4\mathrm{CH_4}CH4​ gives 111 mole of CO2\mathrm{CO_2}CO2​,

n(CH4)=0.5 moln(\mathrm{CH_4}) = 0.5\ \mathrm{mol}n(CH4​)=0.5 mol
  1. Find molar mass of methane
M(CH4)=12+4(1)=16 g mol−1M(\mathrm{CH_4}) = 12 + 4(1) = 16\ \mathrm{g\,mol^{-1}}M(CH4​)=12+4(1)=16 gmol−1
  1. Calculate mass of methane required
m(CH4)=n×M=0.5×16=8 gm(\mathrm{CH_4}) = n \times M = 0.5 \times 16 = 8\ \mathrm{g}m(CH4​)=n×M=0.5×16=8 g

Final Answer

8\boxed{8}8​

The derived answer matches the stored correct answer.

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