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Some Basic Concepts of Chemistry question

2024 · 8 Apr · Shift 1 · Q1
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Some Basic Concepts of Chemistry question

2024 · 8 Apr · Shift 1 · Q1

JEE MainChemistrySome Basic Concepts of ChemistryMCQ+4 / −1
Combustion of glucose (C6H12O6)(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6)(C6​H12​O6​) produces CO2\mathrm{CO}_2CO2​ and water. The amount of oxygen (in g\mathrm{g}g) required for the complete combustion of 900 g900 \mathrm{~g}900 g of glucose is : [Molar mass of glucose in g mol−1=180\mathrm{g} \mathrm{~mol}^{-1}=180g mol−1=180]
  1. A
    32
  2. B
    480
  3. C
    800
  4. D
    960
View written solutionFree

Correct answer: D

  1. Write the balanced combustion reaction

For complete combustion of glucose:

C6H12O6+6O2→6CO2+6H2O\mathrm{C_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O}C6​H12​O6​+6O2​→6CO2​+6H2​O

So, 1 mole of glucose requires 6 moles of O2\mathrm{O_2}O2​.

  1. Calculate moles of glucose present

Given mass of glucose =900 g= 900\,\text{g}=900g

Molar mass of glucose =180 g mol−1= 180\,\text{g mol}^{-1}=180g mol−1

Moles of glucose=900180=5\text{Moles of glucose} = \frac{900}{180} = 5Moles of glucose=180900​=5
  1. Calculate moles of oxygen required

From the balanced equation:

1 mol glucose→6 mol O21\text{ mol glucose} \rightarrow 6\text{ mol } O_21 mol glucose→6 mol O2​

Therefore,

5 mol glucose→5×6=30 mol O25\text{ mol glucose} \rightarrow 5 \times 6 = 30\text{ mol } O_25 mol glucose→5×6=30 mol O2​
  1. Convert moles of oxygen to mass

Molar mass of O2=32 g mol−1\mathrm{O_2} = 32\,\text{g mol}^{-1}O2​=32g mol−1

Mass of O2=30×32=960 g\text{Mass of } O_2 = 30 \times 32 = 960\,\text{g}Mass of O2​=30×32=960g
  1. Check options
  • A: 32
  • B: 480
  • C: 800
  • D: 960

Hence, the correct option is:

D: 960 g\boxed{\text{D: } 960\,\text{g}}D: 960g​
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