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Some Basic Concepts of Chemistry question

2024 · 5 Apr · Shift 2 · Q16
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  5. /2024 · 5 Apr · Shift 2 · Q16

Some Basic Concepts of Chemistry question

2024 · 5 Apr · Shift 2 · Q16

JEE MainChemistrySome Basic Concepts of ChemistryMCQ+4 / −1
The number of moles of methane required to produce 11 g CO2(g)11 \mathrm{~g} \mathrm{~CO}_2(\mathrm{g})11 g CO2​(g) after complete combustion is : (Given molar mass of methane in g mol−1:16\mathrm{g} \mathrm{~mol}^{-1}: 16g mol−1:16 )
  1. A
    0.35
  2. B
    0.25
  3. C
    0.5
  4. D
    0.75
View written solutionFree

Correct answer: B

  1. Write the balanced combustion reaction of methane
CH4+2O2→CO2+2H2O\mathrm{CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O}CH4​+2O2​→CO2​+2H2​O

From the equation,

  • 111 mole of CH4\mathrm{CH_4}CH4​ produces 111 mole of CO2\mathrm{CO_2}CO2​.
  1. Calculate moles of CO2\mathrm{CO_2}CO2​ formed

Molar mass of CO2\mathrm{CO_2}CO2​:

12+2×16=44 g mol−112 + 2\times 16 = 44\ \mathrm{g\,mol^{-1}}12+2×16=44 gmol−1

Given mass of CO2=11 g\mathrm{CO_2} = 11\ \mathrm{g}CO2​=11 g,

moles of CO2=1144=0.25\text{moles of } \mathrm{CO_2} = \frac{11}{44} = 0.25moles of CO2​=4411​=0.25
  1. Use stoichiometric ratio

Since

CH4:CO2=1:1\mathrm{CH_4 : CO_2} = 1:1CH4​:CO2​=1:1

therefore,

moles of CH4=0.25\text{moles of } \mathrm{CH_4} = 0.25moles of CH4​=0.25
  1. Check options
  • A: 0.350.350.35 ✗
  • B: 0.250.250.25 ✓
  • C: 0.50.50.5 ✗
  • D: 0.750.750.75 ✗

Hence, the correct answer is B.

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