1. Write the reaction conceptually

Aniline reacts with an acetylating agent to form acetanilide in a 1 : 1 molar ratio.

$\text{Aniline} \rightarrow \text{Acetanilide}$

So, moles of acetanilide formed = moles of aniline taken.

2. Calculate molar mass of aniline

Aniline is $\mathrm{C_6H_5NH_2} = \mathrm{C_6H_7N}$

$M(\text{aniline}) = 6\times 12 + 7\times 1 + 14 = 72 + 7 + 14 = 93\,\mathrm{g\,mol^{-1}}$

3. Find moles of aniline

Given mass of aniline = $6.55\,\mathrm{g}$

$n(\text{aniline}) = \frac{6.55}{93}$

$n(\text{aniline}) \approx 0.07043\,\mathrm{mol}$

4. Calculate molar mass of acetanilide

Acetanilide is $\mathrm{C_6H_5NHCOCH_3} = \mathrm{C_8H_9NO}$

$M(\text{acetanilide}) = 8\times 12 + 9\times 1 + 14 + 16 = 96 + 9 + 14 + 16 = 135\,\mathrm{g\,mol^{-1}}$

5. Find mass of acetanilide formed

Since molar ratio is $1:1$,

$n(\text{acetanilide}) = 0.07043\,\mathrm{mol}$

Hence,

$m(\text{acetanilide}) = n \times M = 0.07043 \times 135$

$m(\text{acetanilide}) \approx 9.51\,\mathrm{g}$

6. Match with the required format

The question asks:

$\underline{\hspace{2cm}} \times 10^{-1}\,\mathrm{g}$

Now,

$9.51\,\mathrm{g} = 95.1 \times 10^{-1}\,\mathrm{g}$

So the required integer is

$\boxed{95}$

7. Comparison with stored correct answer

Stored correct answer = $95$

Our derived answer = $95$

So they agree.