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Some Basic Concepts of Chemistry question

2024 · 4 Apr · Shift 1 · Q13
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Some Basic Concepts of Chemistry question

2024 · 4 Apr · Shift 1 · Q13

JEE MainChemistrySome Basic Concepts of ChemistryMCQ+4 / −1
The Molarity (M) of an aqueous solution containing 5.85 g5.85 \mathrm{~g}5.85 g of NaCl\mathrm{NaCl}NaCl in 500 mL500 \mathrm{~mL}500 mL water is : (Given : Molar Mass Na:23\mathrm{Na}: 23Na:23 and Cl:35.5 gmol−1\mathrm{Cl}: 35.5 \mathrm{~gmol}^{-1}Cl:35.5 gmol−1)
  1. A
    20
  2. B
    4
  3. C
    2
  4. D
    0.2
View written solutionFree

Correct answer: D

  1. Find molar mass of NaCl

M(NaCl)=M(Na)+M(Cl)=23+35.5=58.5 g mol−1M(\mathrm{NaCl}) = M(\mathrm{Na}) + M(\mathrm{Cl}) = 23 + 35.5 = 58.5\ \mathrm{g\,mol^{-1}}M(NaCl)=M(Na)+M(Cl)=23+35.5=58.5 gmol−1

  1. Calculate moles of NaCl

Given mass of NaCl = 5.85 g5.85\,\mathrm{g}5.85g

n=massmolar mass=5.8558.5=0.1 moln = \frac{\text{mass}}{\text{molar mass}} = \frac{5.85}{58.5} = 0.1\ \mathrm{mol}n=molar massmass​=58.55.85​=0.1 mol

  1. Convert volume into litres

Given volume = 500 mL500\,\mathrm{mL}500mL

500 mL=0.5 L500\,\mathrm{mL} = 0.5\,\mathrm{L}500mL=0.5L

  1. Calculate molarity

Molarity is defined as:

M=moles of solutevolume of solution in litresM = \frac{\text{moles of solute}}{\text{volume of solution in litres}}M=volume of solution in litresmoles of solute​

So,

M=0.10.5=0.2 MM = \frac{0.1}{0.5} = 0.2\,\mathrm{M}M=0.50.1​=0.2M

  1. Match with the options
  • A: 20
  • B: 4
  • C: 2
  • D: 0.2

Hence, the correct option is:

D (0.2)\boxed{\text{D }(0.2)}D (0.2)​

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