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Some Basic Concepts of Chemistry question

2022 · 28 Jul · Shift 1 · Q22
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Some Basic Concepts of Chemistry question

2022 · 28 Jul · Shift 1 · Q22

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
On complete combustion of 0.492 g0.492 \mathrm{~g}0.492 g of an organic compound containing C,H\mathrm{C}, \mathrm{H}C,H and O\mathrm{O}O, 0.7938 g0.7938 \mathrm{~g}0.7938 g of CO2\mathrm{CO}_{2}CO2​ and 0.4428 g0.4428 \mathrm{~g}0.4428 g of H2O\mathrm{H}_{2} \mathrm{O}H2​O was produced. The % composition of oxygen in the compound is ‾\underline{\hspace{2cm}}​.
Numerical answer
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Correct answer: 46

  1. Find mass of carbon from CO2\mathrm{CO_2}CO2​

Since 44 g44\text{ g}44 g of CO2\mathrm{CO_2}CO2​ contains 12 g12\text{ g}12 g of carbon,

Mass of C=0.7938×1244\text{Mass of C} = 0.7938\times \frac{12}{44}Mass of C=0.7938×4412​ Mass of C=0.21649 g≈0.2165 g\text{Mass of C} = 0.21649\text{ g} \approx 0.2165\text{ g}Mass of C=0.21649 g≈0.2165 g
  1. Find mass of hydrogen from H2O\mathrm{H_2O}H2​O

Since 18 g18\text{ g}18 g of H2O\mathrm{H_2O}H2​O contains 2 g2\text{ g}2 g of hydrogen,

Mass of H=0.4428×218\text{Mass of H} = 0.4428\times \frac{2}{18}Mass of H=0.4428×182​ Mass of H=0.0492 g\text{Mass of H} = 0.0492\text{ g}Mass of H=0.0492 g
  1. Find mass of oxygen in the compound

The compound contains only C, H, and O. Therefore,

Mass of O=Total mass−(Mass of C+Mass of H)\text{Mass of O} = \text{Total mass} - (\text{Mass of C} + \text{Mass of H})Mass of O=Total mass−(Mass of C+Mass of H) Mass of O=0.492−(0.21649+0.0492)\text{Mass of O} = 0.492 - (0.21649 + 0.0492)Mass of O=0.492−(0.21649+0.0492) Mass of O=0.492−0.26569=0.22631 g\text{Mass of O} = 0.492 - 0.26569 = 0.22631\text{ g}Mass of O=0.492−0.26569=0.22631 g
  1. Calculate percentage of oxygen
%O=0.226310.492×100\%\text{O} = \frac{0.22631}{0.492}\times 100%O=0.4920.22631​×100 %O≈45.998%≈46%\%\text{O} \approx 45.998\% \approx 46\%%O≈45.998%≈46%
  1. Final Answer

The percentage composition of oxygen in the compound is

46\boxed{46}46​
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