1. Given data

• Mass of organic compound $= 0.492\,\text{g}$
• On complete combustion:
  • Mass of $CO_2 = 0.793\,\text{g}$
  • Mass of $H_2O = 0.442\,\text{g}$

The compound contains only $C$, $H$, and $O$.

2. Mass of carbon in the compound

All carbon in the compound goes to $CO_2$.

$\text{Mass of C} = 0.793 \times \frac{12}{44}$

$\text{Mass of C} = 0.21627\,\text{g}$

3. Mass of hydrogen in the compound

All hydrogen in the compound goes to $H_2O$.

$\text{Mass of H} = 0.442 \times \frac{2}{18}$

$\text{Mass of H} = 0.04911\,\text{g}$

4. Mass of oxygen in the compound

Since the compound contains only $C$, $H$, and $O$,

$\text{Mass of O} = \text{Mass of compound} - (\text{Mass of C} + \text{Mass of H})$

$\text{Mass of O} = 0.492 - (0.21627 + 0.04911)$

$\text{Mass of O} = 0.22662\,\text{g}$

5. Percentage of oxygen

$\%\,O = \frac{0.22662}{0.492} \times 100$

$\%\,O = 46.06\%$

Nearest integer:

$\boxed{46}$

6. Comparison with stored answer

Stored correct answer $= 46$

Our derived answer $= 46$

So, the answer agrees with the stored correct answer.