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Some Basic Concepts of Chemistry question

2021 · 24 Feb · Shift 2 · Q15

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Some Basic Concepts of Chemistry
2021 · 24 Feb · Shift 2 · Q15

Some Basic Concepts of Chemistry question

2021 · 24 Feb · Shift 2 · Q15

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1

The formula of a gaseous hydrocarbon which requires 6 times of its own volume of

O_2

for complete oxidation and produces 4 times its own volume of

CO_2

is CxHy. The value of y is

\underline{\hspace{2cm}}

.

Numerical answer

View written solutionFree

Correct answer: 8

Let the gaseous hydrocarbon be $\mathrm{C_xH_y}$ .
For complete combustion, the balanced reaction is:

\mathrm{C_xH_y + \left(x + \frac{y}{4}\right)O_2 \rightarrow xCO_2 + \frac{y}{2}H_2O}

Since all gases are compared at the same temperature and pressure, volumes are proportional to mole ratios.
Given:

Hydrocarbon requires $6$ times its own volume of $O_2$
Hydrocarbon produces $4$ times its own volume of $CO_2$

So from the reaction stoichiometry:

x + \frac{y}{4} = 6

and

x = 4

Substitute $x=4$ into the first equation:

4 + \frac{y}{4} = 6

\frac{y}{4} = 2

y = 8

Therefore, the hydrocarbon is $\mathrm{C_4H_8}$ , and the required value is:

\boxed{8}

Comparison with stored correct answer:

Derived answer = $8$
Stored correct answer = $8$
They match.

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