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Some Basic Concepts of Chemistry question

2021 · 25 Feb · Shift 1 · Q10

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Some Basic Concepts of Chemistry
2021 · 25 Feb · Shift 1 · Q10

Some Basic Concepts of Chemistry question

2021 · 25 Feb · Shift 1 · Q10

JEE MainChemistrySome Basic Concepts of ChemistryMCQ+4 / −1

Complete combustion of 1.80 g of an oxygen containing compound (

C_xH_yO_z

) gave 2.64 g of

CO_2

and 1.08 g of

H_2O

. The percentage of oxygen in the organic compound is :

A
51.63
B
50.33
C
63.53
D
53.33

View written solutionFree

Correct answer: D

Find mass of carbon in the compound

From combustion: $2.64\,\text{g } CO_2$

In $44$ g of $CO_2$ , mass of carbon is $12$ g. So, mass of carbon in $2.64$ g $CO_2$ is $m_C = 2.64 \times \frac{12}{44} = 0.72\,\text{g}$

Find mass of hydrogen in the compound

From combustion: $1.08\,\text{g } H_2O$

In $18$ g of $H_2O$ , mass of hydrogen is $2$ g. So, mass of hydrogen in $1.08$ g $H_2O$ is $m_H = 1.08 \times \frac{2}{18} = 0.12\,\text{g}$

Find mass of oxygen in the original compound

Total mass of compound burnt = $1.80$ g

Hence, $m_O = 1.80 - (0.72 + 0.12) = 1.80 - 0.84 = 0.96\,\text{g}$

Calculate percentage of oxygen

$\%O = \frac{0.96}{1.80} \times 100$

$\%O = 53.33\%$

Match with options

Thus the correct option is: $\boxed{\text{D: }53.33}$

Comparison with stored answer

Stored correct answer is D, which matches our derived answer.

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