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Some Basic Concepts of Chemistry question

2021 · 22 Jul · Shift 2 · Q23
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Some Basic Concepts of Chemistry question

2021 · 22 Jul · Shift 2 · Q23

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
If the concentration of glucose (C6H12O6C_6H_{12}O_6C6​H12​O6​) in blood is 0.72 g L −-− 1, the molarity of glucose in blood is ‾×\underline{\hspace{2cm}}\times​× 10 −-− 3 M. (Nearest integer) [Given : Atomic mass of C = 12, H = 1, O = 16 u]
Numerical answer
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Correct answer: 4

  1. Given data

    • Concentration of glucose =0.72 g L−1= 0.72\,\text{g L}^{-1}=0.72g L−1
    • Formula of glucose =C6H12O6= C_6H_{12}O_6=C6​H12​O6​

  2. Calculate molar mass of glucose M(C6H12O6)=6(12)+12(1)+6(16)M(C_6H_{12}O_6)=6(12)+12(1)+6(16)M(C6​H12​O6​)=6(12)+12(1)+6(16) =72+12+96=180 g mol−1=72+12+96=180\,\text{g mol}^{-1}=72+12+96=180g mol−1

  3. Use molarity formula Molarity is moles of solute per litre of solution: Molarity=mass per litremolar mass\text{Molarity} = \frac{\text{mass per litre}}{\text{molar mass}}Molarity=molar massmass per litre​

    So, Molarity=0.72180\text{Molarity} = \frac{0.72}{180}Molarity=1800.72​ =0.004 mol L−1=0.004\,\text{mol L}^{-1}=0.004mol L−1

  4. Write in scientific notation 0.004=4×10−3 M0.004 = 4 \times 10^{-3}\,\text{M}0.004=4×10−3M

  5. Nearest integer for the blank The blank is 444.

Final Answer: 444

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