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Some Basic Concepts of Chemistry question

2021 · 20 Jul · Shift 1 · Q20
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Some Basic Concepts of Chemistry question

2021 · 20 Jul · Shift 1 · Q20

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
An average person needs about 10000 kJ energy per day. The amount of glucose (molar mass = 180.0 g mol −-− 1) needed to meet this energy requirement is ‾\underline{\hspace{2cm}}​ g. (Use : Δ\DeltaΔ CH(glucose) = −-− 2700 kJ mol −-− 1)
Numerical answer
View written solutionFree

Correct answer: 667

  1. Given data

    • Energy needed per day =10000 kJ= 10000\ \text{kJ}=10000 kJ
    • Enthalpy of combustion of glucose: ΔcH(glucose)=−2700 kJ mol−1\Delta_c H(\text{glucose}) = -2700\ \text{kJ mol}^{-1}Δc​H(glucose)=−2700 kJ mol−1
    • Molar mass of glucose =180.0 g mol−1= 180.0\ \text{g mol}^{-1}=180.0 g mol−1

  2. Interpretation One mole of glucose releases 2700 kJ2700\ \text{kJ}2700 kJ of energy on combustion.

  3. Moles of glucose required n=100002700=3.7037 moln = \frac{10000}{2700} = 3.7037\ \text{mol}n=270010000​=3.7037 mol

  4. Mass of glucose required m=n×M=3.7037×180.0m = n \times M = 3.7037 \times 180.0m=n×M=3.7037×180.0 m=666.67 gm = 666.67\ \text{g}m=666.67 g

  5. Final integer answer m≈667 gm \approx 667\ \text{g}m≈667 g

  6. Comparison with stored answer Stored correct answer = 667667667

    This matches the derived answer.

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