JEE MainChemistrySolutionsMCQ+4 / −1
Given below are two statements: Statement (I) : Molal depression constant is given by , where symbols have their usual meaning. Statement (II) : for benzene is less than the for water. In the light of the above statements, choose the most appropriate answer from the options given below :
- AStatement I is correct but Statement II is incorrect
- BBoth Statement I and Statement II are incorrect
- CStatement I is incorrect but Statement II is correct
- DBoth Statement I and Statement II are correct
View written solutionFree
Correct answer: A
- Check Statement (I)
For depression in freezing point,
and the cryoscopic constant is
If we use
then
Substituting:
= \frac{R T_f M_1}{1000\,\Delta S_{\text{fus}}}$$ If $M_1$ is taken in $\text{g mol}^{-1}$, the factor $1000$ is absorbed in the usual practical expression depending on unit convention. Thus the given relation $$K_f = \frac{M_1 R T_f}{\Delta S_{\text{fus}}}$$ is the standard form in that convention. So, **Statement (I) is correct**. --- 2. **Check Statement (II)** Known values of cryoscopic constants are approximately: - For water: $$K_f \approx 1.86\ \text{K kg mol}^{-1}$$ - For benzene: $$K_f \approx 5.12\ \text{K kg mol}^{-1}$$ Therefore, $$K_f(\text{benzene}) > K_f(\text{water})$$ So the statement " $K_f$ for benzene is less than the $K_f$ for water" is **incorrect**. --- 3. **Choose the correct option** - Statement I: Correct - Statement II: Incorrect Hence, the correct option is: $$\boxed{\text{A}}$$ --- 4. **Comparison with stored answer** Stored correct answer: **A** My derived answer: **A** They match.More from Solutions
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