1. Identify the behavior of each solution

(A) Solution of chloroform and acetone

Chloroform and acetone show strong intermolecular hydrogen bonding between $\text{CHCl}_3 \quad \text{and} \quad (CH_3)_2CO$ This causes negative deviation from Raoult’s law.

Negative deviation leads to a maximum boiling azeotrope.

So, $(A) \to (III)$

(B) Solution of ethanol and water

Ethanol and water form a solution that shows positive deviation from Raoult’s law because mixing disrupts the strong hydrogen-bonding network present in pure water and pure ethanol.

Positive deviation leads to a minimum boiling azeotrope.

So, $(B) \to (I)$

(C) Solution of benzene and toluene

Benzene and toluene are very similar in molecular size and intermolecular forces, so they form an ideal solution.

For an ideal solution, $\Delta V_{\text{mix}} = 0$

So, $(C) \to (IV)$

(D) Solution of acetic acid in benzene

Acetic acid in benzene undergoes association (dimerization) due to hydrogen bonding.

So, $(D) \to (II)$

2. Final matching

Thus the correct match is:

3. Compare with options

This corresponds to Option A.

4. Comparison with stored correct answer

Stored correct answer = A

Our derived answer = A

Hence, the derived answer agrees with the stored correct answer.