Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Solutions question

2025 · 22 Jan · Shift 1 · Q15
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Solutions
  5. /2025 · 22 Jan · Shift 1 · Q15

Solutions question

2025 · 22 Jan · Shift 1 · Q15

JEE MainChemistrySolutionsMCQ+4 / −1
Arrange the following solutions in order of their increasing boiling points. (i) 10−4MNaCl10^{-4} \mathrm{M} \mathrm{NaCl}10−4MNaCl(ii) 10−4M10^{-4} \mathrm{M}10−4M Urea (iii) 10−3MNaCl10^{-3} \mathrm{M} \mathrm{NaCl}10−3MNaCl(iv) 10−2MNaCl10^{-2} \mathrm{M} \mathrm{NaCl}10−2MNaCl
  1. A
    ((( i )<()\lt ()<( ii )<()\lt ()<( iii )<()\lt ()<( iv )))
  2. B
    (ii) <(\lt (<( i )<()\lt ()<( iii )<()\lt ()<( iv )))
  3. C
    (iv) <(\lt (<( iii )<()\lt ()<( i )<()\lt ()<( ii )))
  4. D
    (ii) <\lt<(i) ≡\equiv≡(iii) <\lt< (iv)
View written solutionFree

Correct answer: B

  1. Use boiling point elevation relation

For dilute solutions, ΔTb=iKbm\Delta T_b = i K_b mΔTb​=iKb​m where:

  • iii = van’t Hoff factor
  • KbK_bKb​ = ebullioscopic constant of solvent
  • mmm = molality

Since all are very dilute aqueous solutions, we compare i×i \timesi× concentration directly.


  1. Find effective particle concentration for each solution
  • (i) 10−4 M NaCl10^{-4}\,\text{M NaCl}10−4M NaCl

    NaCl dissociates as: NaCl→Na++Cl−\text{NaCl} \rightarrow \text{Na}^+ + \text{Cl}^-NaCl→Na++Cl− So, ideally i≈2i \approx 2i≈2. Hence relative boiling point elevation: iC=2×10−4=2×10−4iC = 2 \times 10^{-4} = 2 \times 10^{-4}iC=2×10−4=2×10−4

  • (ii) 10−4 M urea10^{-4}\,\text{M urea}10−4M urea

    Urea is a non-electrolyte, so: i=1i=1i=1 Hence, iC=1×10−4=10−4iC = 1 \times 10^{-4} = 10^{-4}iC=1×10−4=10−4

  • (iii) 10−3 M NaCl10^{-3}\,\text{M NaCl}10−3M NaCl iC=2×10−3iC = 2 \times 10^{-3}iC=2×10−3

  • (iv) 10−2 M NaCl10^{-2}\,\text{M NaCl}10−2M NaCl iC=2×10−2iC = 2 \times 10^{-2}iC=2×10−2


  1. Compare boiling point elevations

Greater ΔTb\Delta T_bΔTb​ means greater boiling point.

So the increasing order is: 10−4<2×10−4<2×10−3<2×10−210^{-4} < 2\times 10^{-4} < 2\times 10^{-3} < 2\times 10^{-2}10−4<2×10−4<2×10−3<2×10−2 which corresponds to: (ii)<(i)<(iii)<(iv)(ii) < (i) < (iii) < (iv)(ii)<(i)<(iii)<(iv)


  1. Match with the options

This matches Option B.


  1. Comparison with stored correct answer

Stored correct answer: B

Our derived answer: B

So, they agree.

PreviousNext

More from Solutions

  • When a non-volatile solute is added to the solvent, the vapour pressure of the solvent decreases by 10 mm of Hg . The mole fraction of the solute in the solution is 0.2 . What would be the mole fraction of the solvent if decrease in vapour…2025 · MCQ
  • Consider a binary solution of two volatile liquid components 1 and 2.x1​ and y1​ are the mole fractions of component 1 in liquid and vapour phase, respectively. The slope and intercept of the linear plot of x1​1​ vs y1​1​…2025 · MCQ
  • Consider the given plots of vapour pressure (VP) vs temperature(T/K). Which amongst the following options is correct graphical representation showing ΔTf​, depression in the freezing point of a solvent in a…2025 · MCQ
  • What is the freezing point depression constant of a solvent, 50 g of which contain 1 g non volatile solute (molar mass 256 g mol−1 ) and the decrease in freezing point is 0.40 K ?2025 · MCQ
  • Assume a living cell with 0.9% (w/w) of glucose solution (aqueous). This cell is immersed in another solution having equal mole fraction of glucose and water. (Consider the data upto first decimal place only) The cell will :2025 · MCQ
  • 1.24 g of AX2​ (molar mass 124 g mol−1) is dissolved in 1 kg of water to form a solution with boiling point of 100.015°C, while 25.4 g of AY2​ (molar mass 250 g mol−1) in 2 kg of water constitutes a solution with a boiling point of…2025 · MCQ
  • If A2​B is 30% ionised in an aqueous solution, then the value of van't Hoff factor (i) is ​ × 10−1.2025 · Numerical
  • Given below are two statements : Statement (I): NaCl is added to the ice at 0°C, present in the ice cream box to prevent the melting of ice cream. Statement (II): On addition of NaCl to ice at 0°C, there is a depression in freezing point.…2025 · MCQ