1. Use osmotic pressure relation

For dilute solutions, $\pi = iCRT$ where:

• $i$ = van't Hoff factor
• $C$ = molarity
• $R = 0.083\,\text{L bar mol}^{-1}\text{K}^{-1}$
• $T = 300\,\text{K}$

2. Find osmotic pressure inside the artificial cell

Inside the cell: $0.2\,\text{M}$ glucose

Glucose is a non-electrolyte, so $i=1$ Hence, $\pi_{\text{in}} = 1 \times 0.2 \times 0.083 \times 300$ $\pi_{\text{in}} = 4.98\,\text{bar}$

3. Find osmotic pressure outside the cell

Outside solution: $0.05\,\text{M NaCl}$

Given complete dissociation, $\text{NaCl} \rightarrow \text{Na}^+ + \text{Cl}^-$ So, $i=2$ Thus effective concentration is $iC = 2 \times 0.05 = 0.10$ Therefore, $\pi_{\text{out}} = 2 \times 0.05 \times 0.083 \times 300$ $\pi_{\text{out}} = 2.49\,\text{bar}$

4. Net osmotic pressure developed across the membrane

The osmotic pressure developed is the difference: $\Delta \pi = \pi_{\text{in}} - \pi_{\text{out}}$ $\Delta \pi = 4.98 - 2.49 = 2.49\,\text{bar}$

5. Match with the required form

Given answer is to be filled as $\underline{\hspace{2cm}} \times 10^{-1}\,\text{bar}$

Now, $2.49\,\text{bar} = 24.9 \times 10^{-1}\,\text{bar}$ Nearest integer $= 25$

Final Answer

$25$