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Solutions question

2024 · 9 Apr · Shift 1 · Q4
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Solutions question

2024 · 9 Apr · Shift 1 · Q4

JEE MainChemistrySolutionsMCQ+4 / −1
0.05M CuSO40.05 \mathrm{M} \mathrm{~CuSO}_40.05M CuSO4​ when treated with 0.01M K2Cr2O70.01 \mathrm{M} \mathrm{~K}_2 \mathrm{Cr}_2 \mathrm{O}_70.01M K2​Cr2​O7​ gives green colour solution of Cu2Cr2O7\mathrm{Cu}_2 \mathrm{Cr}_2 \mathrm{O}_7Cu2​Cr2​O7​. The two solutions are separated as shown below : [SPM : Semi Permeable Membrane] JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Solutions Question 29 English Due to osmosis :
  1. A
    Molarity of K2Cr2O7\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7K2​Cr2​O7​ solution is lowered.
  2. B
    Green colour formation observed on side Y.
  3. C
    Molarity of CuSO4\mathrm{CuSO}_4CuSO4​ solution is lowered.
  4. D
    Green colour formation observed on side X.
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