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Solutions question

2024 · 29 Jan · Shift 1 · Q30
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Solutions question

2024 · 29 Jan · Shift 1 · Q30

JEE MainChemistrySolutionsNumerical+4 / −1
The osmotic pressure of a dilute solution is 7×105 Pa7 \times 10^5 \mathrm{~Pa}7×105 Pa at 273 K273 \mathrm{~K}273 K. Osmotic pressure of the same solution at 283 K283 \mathrm{~K}283 K is ‾\underline{\hspace{2cm}}​×104Nm−2\times 10^4 \mathrm{Nm}^{-2}×104Nm−2.
Numerical answer
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