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Solutions question

2024 · 6 Apr · Shift 2 · Q23
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Solutions question

2024 · 6 Apr · Shift 2 · Q23

JEE MainChemistrySolutionsNumerical+4 / −1
When 'xxx' ×10−2 mL\times 10^{-2} \mathrm{~mL}×10−2 mL methanol (molar mass =32 g=32 \mathrm{~g}=32 g' density =0.792 g/cm3=0.792 \mathrm{~g} / \mathrm{cm}^3=0.792 g/cm3) is added to 100 mL100 \mathrm{~mL}100 mL. water (density =1 g/cm3=1 \mathrm{~g} / \mathrm{cm}^3=1 g/cm3), the following diagram is obtained. JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Solutions Question 23 English x=x=x=‾\underline{\hspace{2cm}}​ (nearest integer). [Given : Molal freezing point depression constant of water at 273.15 K273.15 \mathrm{~K}273.15 K is 1.86 K kg mol−11.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}1.86 K kg mol−1]
Numerical answer
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