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Redox Reactions question

2024 · 27 Jan · Shift 2 · Q13
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Redox Reactions question

2024 · 27 Jan · Shift 2 · Q13

JEE MainChemistryRedox ReactionsMCQ+4 / −1
Which of the following cannot function as an oxidising agent?
  1. A
    SO42−\mathrm{SO}_4^{2-}SO42−​
  2. B
    MnO4−\mathrm{MnO}_4^{-}MnO4−​
  3. C
    N3−\mathrm{N}^{3-}N3−
  4. D
    BrO3−\mathrm{BrO}_3^{-}BrO3−​
View written solutionFree

Correct answer: C

  1. Idea: An oxidising agent is a species that gets reduced itself, i.e. it should be able to accept electrons.

  2. So we check the oxidation state of the central atom in each species:

    • A. SO42−\mathrm{SO_4^{2-}}SO42−​

      Let oxidation state of S be xxx: x+4(−2)=−2x + 4(-2) = -2x+4(−2)=−2 x−8=−2x - 8 = -2x−8=−2 x=+6x = +6x=+6 Sulfur is in a high oxidation state, so it can be reduced and hence can act as an oxidising agent.

    • B. MnO4−\mathrm{MnO_4^-}MnO4−​

      Let oxidation state of Mn be xxx: x+4(−2)=−1x + 4(-2) = -1x+4(−2)=−1 x−8=−1x - 8 = -1x−8=−1 x=+7x = +7x=+7 Manganese is in its maximum/common highest oxidation state, so permanganate is a strong oxidising agent.

    • C. N3−\mathrm{N^{3-}}N3−

      Oxidation state of nitrogen is −3-3−3. This is the lowest possible oxidation state of nitrogen, so it cannot be reduced further. Therefore it cannot accept electrons and hence cannot act as an oxidising agent.

    • D. BrO3−\mathrm{BrO_3^-}BrO3−​

      Let oxidation state of Br be xxx: x+3(−2)=−1x + 3(-2) = -1x+3(−2)=−1 x−6=−1x - 6 = -1x−6=−1 x=+5x = +5x=+5 Bromine in +5+5+5 oxidation state can still be reduced, so bromate can act as an oxidising agent.

  3. Conclusion: The species that cannot function as an oxidising agent is: N3−\boxed{\mathrm{N^{3-}}}N3−​

  4. Option check:

    • A: Can act as oxidising agent
    • B: Can act as oxidising agent
    • C: Cannot act as oxidising agent
    • D: Can act as oxidising agent
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