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Practical Organic Chemistry question

2023 · 13 Apr · Shift 2 · Q14
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Practical Organic Chemistry question

2023 · 13 Apr · Shift 2 · Q14

JEE MainChemistryPractical Organic ChemistryNumerical+4 / −1
0.400 g0.400 \mathrm{~g}0.400 g of an organic compound (X)(\mathrm{X})(X) gave 0.376 g0.376 \mathrm{~g}0.376 g of AgBr\mathrm{AgBr}AgBr in Carius method for estimation of bromine. %\%% of bromine in the compound (X)(\mathrm{X})(X) is ‾\underline{\hspace{2cm}}​. (Given: Molar mass AgBr=188 g mol−1Br=80 g mol−1\mathrm{AgBr=188~g~mol^{-1}}\mathrm{Br}=80 \mathrm{~g} \mathrm{~mol}^{-1}AgBr=188 g mol−1Br=80 g mol−1)
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