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Periodic Table and Periodicity question

2024 · 29 Jan · Shift 2 · Q4
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Periodic Table and Periodicity question

2024 · 29 Jan · Shift 2 · Q4

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1
Given below are two statements: Statement I : Fluorine has most negative electron gain enthalpy in its group. Statement II : Oxygen has least negative electron gain enthalpy in its group. In the light of the above statements, choose the most appropriate from the options given below
  1. A
    Both Statement I and Statement II are true
  2. B
    Both Statement I and Statement II are false
  3. C
    Statement I is false but Statement II is true
  4. D
    Statement I is true but Statement II is false
View written solutionFree

Correct answer: C

  1. Recall the trend of electron gain enthalpy

Electron gain enthalpy generally becomes more negative across a period and less negative down a group, but there are important exceptions due to very small size and electron-electron repulsions.

  1. Check Statement I: "Fluorine has most negative electron gain enthalpy in its group."

Fluorine belongs to Group 17.

Expected trend might suggest fluorine should have the most negative value, but actually:

  • Chlorine has more negative electron gain enthalpy than fluorine.
  • Reason: fluorine is very small, so the added electron enters a compact 2p2p2p orbital where electron-electron repulsion is high.

Thus, ΔegH(Cl)<ΔegH(F)\Delta_{eg}H(\mathrm{Cl}) < \Delta_{eg}H(\mathrm{F})Δeg​H(Cl)<Δeg​H(F) (in the sense that chlorine is more negative).

So, Statement I is false.

  1. Check Statement II: "Oxygen has least negative electron gain enthalpy in its group."

Oxygen belongs to Group 16.

In this group:

  • Sulfur has more negative electron gain enthalpy than oxygen.
  • Oxygen, because of its very small size, has higher interelectronic repulsion when an extra electron is added.

Also, among the commonly compared elements in Group 16, oxygen shows the least negative electron gain enthalpy.

So, Statement II is true.

  1. Evaluate the options
  • A: Both true →\rightarrow→ Incorrect
  • B: Both false →\rightarrow→ Incorrect
  • C: Statement I false, Statement II true →\rightarrow→ Correct
  • D: Statement I true, Statement II false →\rightarrow→ Incorrect
  1. Final answer

The correct option is: C\boxed{\text{C}}C​

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