1. Identify the electronic configuration of each element in List I

We match each element with its ground-state electronic configuration.

• A. $\mathrm{N}$

  Atomic number of nitrogen is $7$.

  Its configuration is: $1s^2 2s^2 2p^3 = [\mathrm{He}]\,2s^2 2p^3$ So, A $\to$ III.

• B. $\mathrm{S}$

  Atomic number of sulfur is $16$.

  Its configuration is: $1s^2 2s^2 2p^6 3s^2 3p^4 = [\mathrm{Ne}]\,3s^2 3p^4$ So, B $\to$ II.

• C. $\mathrm{Br}$

  Atomic number of bromine is $35$.

  Its configuration is: $[\mathrm{Ar}]\,3d^{10}4s^2 4p^5$ So, C $\to$ I.

• D. $\mathrm{Kr}$

  Atomic number of krypton is $36$.

  Its configuration is: $[\mathrm{Ar}]\,3d^{10}4s^2 4p^6$ So, D $\to$ IV.

2. Final matching

Thus the correct match is: $A\text{-}III,\; B\text{-}II,\; C\text{-}I,\; D\text{-}IV$

3. Compare with options

This corresponds to Option C.

4. Comparison with stored correct answer

Stored correct answer is C, which matches our derived answer.