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Periodic Table and Periodicity question

2019 · 11 Jan · Shift 2 · Q20
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Periodic Table and Periodicity question

2019 · 11 Jan · Shift 2 · Q20

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1
The correct option with respect to the Pauling electronegativity values of the element is :
  1. A
    Ga < Ge
  2. B
    Si < Al
  3. C
    Te > Se
  4. D
    P > S
View written solutionFree

Correct answer: A

  1. Recall the trend of Pauling electronegativity

    Electronegativity generally:

    • increases across a period from left to right,
    • decreases down a group from top to bottom, though there can be small exceptions.
  2. Use approximate Pauling electronegativity values

    Relevant values are:

    • χ(Ga)≈1.81\chi(\mathrm{Ga}) \approx 1.81χ(Ga)≈1.81
    • χ(Ge)≈2.01\chi(\mathrm{Ge}) \approx 2.01χ(Ge)≈2.01
    • χ(Si)≈1.90\chi(\mathrm{Si}) \approx 1.90χ(Si)≈1.90
    • χ(Al)≈1.61\chi(\mathrm{Al}) \approx 1.61χ(Al)≈1.61
    • χ(Te)≈2.10\chi(\mathrm{Te}) \approx 2.10χ(Te)≈2.10
    • χ(Se)≈2.55\chi(\mathrm{Se}) \approx 2.55χ(Se)≈2.55
    • χ(P)≈2.19\chi(\mathrm{P}) \approx 2.19χ(P)≈2.19
    • χ(S)≈2.58\chi(\mathrm{S}) \approx 2.58χ(S)≈2.58
  3. Check each option

    Option A: Ga<Ge\mathrm{Ga} < \mathrm{Ge}Ga<Ge

    Compare: 1.81<2.011.81 < 2.011.81<2.01 This is true.

    Option B: Si<Al\mathrm{Si} < \mathrm{Al}Si<Al

    Compare: 1.90<1.611.90 < 1.611.90<1.61 This is false. In fact, Si>Al\mathrm{Si} > \mathrm{Al}Si>Al.

    Option C: Te>Se\mathrm{Te} > \mathrm{Se}Te>Se

    Compare: 2.10>2.552.10 > 2.552.10>2.55 This is false. In fact, Te<Se\mathrm{Te} < \mathrm{Se}Te<Se.

    Option D: P>S\mathrm{P} > \mathrm{S}P>S

    Compare: 2.19>2.582.19 > 2.582.19>2.58 This is false. In fact, P<S\mathrm{P} < \mathrm{S}P<S.

  4. Conclusion

    Only Option A is correct.

    A: Ga<Ge\boxed{\text{A: } \mathrm{Ga} < \mathrm{Ge}}A: Ga<Ge​

  5. Comparison with stored correct answer

    Stored correct answer: A

    My derived answer: A

    Hence, they agree.

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