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Periodic Table and Periodicity question

2019 · 12 Jan · Shift 1 · Q11
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Periodic Table and Periodicity question

2019 · 12 Jan · Shift 1 · Q11

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1
The element with Z = 120 (not yet discovered) will be an/a -
  1. A
    Alkaline earth metal
  2. B
    Alkali metal
  3. C
    Transition metal
  4. D
    Inner transition metal
View written solutionFree

Correct answer: A

  1. Identify the electronic filling after known elements

    The last known noble gas in the currently predicted sequence is element Z=118Z=118Z=118 with configuration ending in: [Rn] 5f146d107s27p6[Rn] \, 5f^{14} 6d^{10} 7s^2 7p^6[Rn]5f146d107s27p6

  2. Next elements after Z=118Z=118Z=118

    After 7p7p7p is completely filled at Z=118Z=118Z=118, the next electrons are expected to enter the 8s8s8s subshell.

    • For Z=119Z=119Z=119: [Og] 8s1[Og] \, 8s^1[Og]8s1 This would be an alkali metal.

    • For Z=120Z=120Z=120: [Og] 8s2[Og] \, 8s^2[Og]8s2

  3. Determine the group from valence configuration

    An outer electronic configuration of ns2ns^2ns2 corresponds to Group 2 elements.

    Group 2 elements are called alkaline earth metals.

  4. Check options

    • A: Alkaline earth metal ightarrow ightarrowightarrow Correct
    • B: Alkali metal ightarrow ightarrowightarrow Incorrect, that would correspond to ns1ns^1ns1
    • C: Transition metal ightarrow ightarrowightarrow Incorrect, transition metals involve filling of ddd subshells
    • D: Inner transition metal ightarrow ightarrowightarrow Incorrect, inner transition metals involve filling of fff subshells
  5. Final answer

    Therefore, the element with Z=120Z=120Z=120 will be an alkaline earth metal.

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