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Periodic Table and Periodicity question

2019 · 9 Jan · Shift 2 · Q14
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Periodic Table and Periodicity question

2019 · 9 Jan · Shift 2 · Q14

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1
When the first electron gain enthalpy (ΔegH)\left( {{\Delta _{eg}}H} \right)(Δeg​H) of oxygen is −-− 141 kJ/mol, its second electron gain enthalpy is :
  1. A
    a more negative value than the first
  2. B
    almost the same as that of the first
  3. C
    negative, but less negative than the first
  4. D
    a positive value
View written solutionFree

Correct answer: D

  1. What is electron gain enthalpy?

    Electron gain enthalpy is the enthalpy change when an electron is added to a gaseous atom or ion.

    For oxygen: O(g)+e−→O−(g)\mathrm{O(g) + e^- \rightarrow O^-(g)}O(g)+e−→O−(g) This is the first electron gain enthalpy, and it is given as: ΔegH1=−141 kJ mol−1\Delta_{eg}H_1 = -141\ \text{kJ mol}^{-1}Δeg​H1​=−141 kJ mol−1

  2. Second electron gain enthalpy

    The second electron is added to an already negatively charged ion: O−(g)+e−→O2−(g)\mathrm{O^-(g) + e^- \rightarrow O^{2-}(g)}O−(g)+e−→O2−(g)

  3. Why is this different from the first?

    In the second step, an electron is being added to a species that already has a negative charge. So the incoming electron experiences strong electrostatic repulsion from the negatively charged ion O−\mathrm{O^-}O−.

    Because energy must be supplied to overcome this repulsion, the process is endothermic.

  4. Sign of second electron gain enthalpy

    Endothermic process means: ΔegH2>0\Delta_{eg}H_2 > 0Δeg​H2​>0

    So the second electron gain enthalpy of oxygen is positive.

  5. Checking options

    • A: more negative than the first → Incorrect
    • B: almost the same as the first → Incorrect
    • C: negative, but less negative than the first → Incorrect
    • D: a positive value → Correct
  6. Final answer

    D: a positive value\boxed{\text{D: a positive value}}D: a positive value​

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