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Periodic Table and Periodicity question

2019 · 8 Apr · Shift 2 · Q18
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Periodic Table and Periodicity question

2019 · 8 Apr · Shift 2 · Q18

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1
The IUPAC symbol for the element with atomic number 119 would be :
  1. A
    uun
  2. B
    une
  3. C
    uue
  4. D
    unh
View written solutionFree

Correct answer: C

  1. Use IUPAC temporary systematic naming rules for undiscovered elements.

  2. For atomic number 119119119, write the digits separately: 1,  1,  91,\;1,\;91,1,9

  3. Replace each digit by its IUPAC root:

    • 1→un1 \to \text{un}1→un
    • 1→un1 \to \text{un}1→un
    • 9→enn9 \to \text{enn}9→enn
  4. Combine the roots and add the ending "iumiumium": un+un+enn+ium=ununennium\text{un} + \text{un} + \text{enn} + \text{ium} = \text{ununennium}un+un+enn+ium=ununennium

  5. The symbol is formed from the first letters of the roots: un→u,un→u,enn→e\text{un} \to u,\quad \text{un} \to u,\quad \text{enn} \to eun→u,un→u,enn→e So the symbol is: Uue\boxed{\text{Uue}}Uue​

  6. Comparing with the options:

    • A: uun\text{uun}uun ❌
    • B: une\text{une}une ❌
    • C: uue\text{uue}uue ✅
    • D: unh\text{unh}unh ❌

Therefore, the correct option is C.

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