Check the color of each compound

We compare the known colors of the given compounds:

• A: Ammonium sulphide, $(NH_4)_2S$
  This is generally colorless in solution, but not known as a characteristic white solid precipitate in this context.

• B: Ammonium arsinomolybdate
  This compound is known to give a yellow precipitate.

• C: Lead iodide, $PbI_2$
  This is a famous bright yellow precipitate.

• D: Lead sulphate, $PbSO_4$
  This is a white precipitate.

Identify the white compound

From the above: $PbSO_4 \text{ is white}$

Correct option

Therefore, the compound that is white in color is: $\boxed{\text{D: Lead sulphate}}$

Comparison with stored correct answer

Stored correct answer = D
Derived answer = D

So, the answers agree.