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P Block Elements question

2023 · 10 Apr · Shift 1 · Q21
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P Block Elements question

2023 · 10 Apr · Shift 1 · Q21

JEE MainChemistryP Block ElementsNumerical+4 / −1
In the following reactions, the total number of oxygen atoms in X and Y is ‾\underline{\hspace{2cm}}​. Na 2_22​ O + H 2_22​ O →\to→ 2X Cl 2_22​ O 7_77​ + H 2_22​ O →\to→ 2Y
Numerical answer
View written solutionFree

Correct answer: 5

  1. Identify compound XXX

Given: Na2O+H2O→2X\mathrm{Na_2O + H_2O \to 2X}Na2​O+H2​O→2X

Sodium oxide reacts with water to form sodium hydroxide: Na2O+H2O→2NaOH\mathrm{Na_2O + H_2O \to 2NaOH}Na2​O+H2​O→2NaOH

So, X=NaOHX = \mathrm{NaOH}X=NaOH

Number of oxygen atoms in one formula unit of XXX: NaOH has 1 oxygen atom\mathrm{NaOH} \text{ has } 1 \text{ oxygen atom}NaOH has 1 oxygen atom

  1. Identify compound YYY

Given: Cl2O7+H2O→2Y\mathrm{Cl_2O_7 + H_2O \to 2Y}Cl2​O7​+H2​O→2Y

Cl2O7\mathrm{Cl_2O_7}Cl2​O7​ is the anhydride of perchloric acid. On reaction with water: Cl2O7+H2O→2HClO4\mathrm{Cl_2O_7 + H_2O \to 2HClO_4}Cl2​O7​+H2​O→2HClO4​

So, Y=HClO4Y = \mathrm{HClO_4}Y=HClO4​

Number of oxygen atoms in one formula unit of YYY: HClO4 has 4 oxygen atoms\mathrm{HClO_4} \text{ has } 4 \text{ oxygen atoms}HClO4​ has 4 oxygen atoms

  1. Total number of oxygen atoms in XXX and YYY

1+4=51 + 4 = 51+4=5

Therefore, the required integer is: 5\boxed{5}5​

  1. Comparison with stored correct answer

Stored correct answer = 555

Our derived answer also = 555, so they agree.

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