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P Block Elements question

2022 · 27 Jul · Shift 1 · Q4
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P Block Elements question

2022 · 27 Jul · Shift 1 · Q4

JEE MainChemistryP Block ElementsMCQ+4 / −1
Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Activated charcoal adsorbs SO2SO_2SO2​ more efficiently than CH4CH_4CH4​. Reason R : Gases with lower critical temperatures are readily adsorbed by activated charcoal. In the light of the above statements, choose the correct answer from the options given below.
  1. A
    Both A and R are correct and R is the correct explanation of A.
  2. B
    Both A and R are correct but R is NOT the correct explanation of A.
  3. C
    A is correct but R is not correct.
  4. D
    A is not correct but R is correct.
View written solutionFree

Correct answer: C

  1. Concept used: adsorption of gases on activated charcoal

    Adsorption of gases on solids is generally greater when the gas is:

    • more easily liquefiable,
    • more polarizable,
    • has higher critical temperature.

    This is because such gases have stronger intermolecular attraction and hence interact more strongly with the surface.

  2. Check Assertion A

    Assertion A: Activated charcoal adsorbs SO2SO_2SO2​ more efficiently than CH4CH_4CH4​.

    • SO2SO_2SO2​ is a polar, highly polarizable gas and is easily liquefiable.
    • CH4CH_4CH4​ is non-polar and less easily liquefiable.

    Therefore, activated charcoal adsorbs SO2SO_2SO2​ more strongly than CH4CH_4CH4​.

    So, Assertion A is correct.

  3. Check Reason R

    Reason R: Gases with lower critical temperatures are readily adsorbed by activated charcoal.

    This is incorrect. The correct statement is:

    Gases with higher critical temperatures are more readily adsorbed.

    Since higher critical temperature means easier liquefaction, adsorption is greater.

    Therefore, Reason R is not correct.

  4. Choose the correct option

    • A is correct
    • R is not correct

    Hence, the correct option is:

    C\boxed{\text{C}}C​

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