Given below are two statements. Statement I : Stannane is an example of a molecular hydride. Statement II : Stannane is a planar molecule. In the light of the above statement, choose the most appropriate answer from the options given below.

Statement I is true but Statement II is false.

Both Statement I and Statement II are true.

Both Statement I and Statement II are false.

Statement I is false but Statement II is true.

P Block Elements PYQ — JEE Main 2022 · 29 Jul · Shift 2 · Q6 with Solution

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Correct answer: C

Identify stannane

Stannane is the hydride of tin with formula $\mathrm{SnH_4}$ It is analogous to methane, silane, and germane.
Check Statement I: “Stannane is an example of a molecular hydride.”

Molecular hydrides are covalent hydrides formed by p-block elements, such as: $\mathrm{CH_4,\, NH_3,\, H_2O,\, SiH_4,\, SnH_4}$

Since stannane, $\mathrm{SnH_4}$ , is a covalent hydride of a p-block element, it is a molecular hydride.

Therefore, Statement I is true.
Check Statement II: “Stannane is a planar molecule.”

In $\mathrm{SnH_4}$ , the central atom Sn forms four sigma bonds with four H atoms and has no lone pair.

By VSEPR theory, a molecule of type $\mathrm{AX_4}$ has tetrahedral geometry, not planar geometry.

So stannane is tetrahedral, not planar.

Therefore, Statement II is false.
Evaluate the options
- A: Both true — incorrect
- B: Both false — incorrect
- C: Statement I true, Statement II false — correct
- D: Statement I false, Statement II true — incorrect
Final answer

The correct option is $\boxed{\text{C}}$

View written solutionFree

Correct answer: C

Identify stannane

Stannane is the hydride of tin with formula $\mathrm{SnH_4}$ It is analogous to methane, silane, and germane.
Check Statement I: “Stannane is an example of a molecular hydride.”

Molecular hydrides are covalent hydrides formed by p-block elements, such as: $\mathrm{CH_4,\, NH_3,\, H_2O,\, SiH_4,\, SnH_4}$

Since stannane, $\mathrm{SnH_4}$ , is a covalent hydride of a p-block element, it is a molecular hydride.

Therefore, Statement I is true.
Check Statement II: “Stannane is a planar molecule.”

In $\mathrm{SnH_4}$ , the central atom Sn forms four sigma bonds with four H atoms and has no lone pair.

By VSEPR theory, a molecule of type $\mathrm{AX_4}$ has tetrahedral geometry, not planar geometry.

So stannane is tetrahedral, not planar.

Therefore, Statement II is false.
Evaluate the options
- A: Both true — incorrect
- B: Both false — incorrect
- C: Statement I true, Statement II false — correct
- D: Statement I false, Statement II true — incorrect
Final answer

The correct option is $\boxed{\text{C}}$