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P Block Elements question

2022 · 29 Jul · Shift 2 · Q5
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  5. /2022 · 29 Jul · Shift 2 · Q5

P Block Elements question

2022 · 29 Jul · Shift 2 · Q5

JEE MainChemistryP Block ElementsMCQ+4 / −1
In liquation process used for tin (Sn), the metal :
  1. A
    is reacted with acid.
  2. B
    is dissolved in water.
  3. C
    is brought to molten form which is made to flow on a slope.
  4. D
    is fused with NaOH
View written solutionFree

Correct answer: C

  1. Recall what liquation means

    Liquation is a method of refining metals having low melting point.

    In this process, the impure metal is heated gently so that it melts, and the molten metal is allowed to flow away from the solid impurities.

  2. Apply this to tin (Sn)(\mathrm{Sn})(Sn)

    Tin is a low-melting metal, so it can be refined by liquation.

    The metal is heated until it becomes molten, and then the molten metal is made to flow on a sloping surface. The impurities, being less fusible, are left behind.

  3. Check each option

    • A: is reacted with acid
      This is not liquation.

    • B: is dissolved in water
      This is incorrect; metals are not refined by dissolving in water in liquation.

    • C: is brought to molten form which is made to flow on a slope
      This exactly matches the liquation process.

    • D: is fused with NaOH
      This is not liquation.

  4. Conclusion

    Therefore, the correct option is:

    C\boxed{\text{C}}C​

  5. Comparison with stored correct answer

    Stored correct answer = C
    Derived answer = C

    Hence, they agree.

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