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Ionic Equilibrium question

2022 · 27 Jul · Shift 1 · Q19

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JEE Main
Chemistry
Ionic Equilibrium
2022 · 27 Jul · Shift 1 · Q19

Ionic Equilibrium question

2022 · 27 Jul · Shift 1 · Q19

JEE MainChemistryIonic EquilibriumNumerical+4 / −1

At

310 \mathrm{~K}

, the solubility of

\mathrm{CaF}_{2}

in water is

2.34 \times 10^{-3} \mathrm{~g} / 100 \mathrm{~mL}

. The solubility product of

\mathrm{CaF}_{2}

is

\underline{\hspace{2cm}}

\times 10^{-8}(\mathrm{~mol} / \mathrm{L})^{3}

. (Give molar mass :

\mathrm{CaF}_{2}=78 \mathrm{~g} \mathrm{~mol}^{-1}

)

Numerical answer

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