Doubts
Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents
Sign in to save progress →
Doubts
Sign in

Ionic Equilibrium question

2022 · 26 Jun · Shift 1 · Q14
Guest · try one question or challengeGuest · try one question or challenge
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Ionic Equilibrium
  5. /2022 · 26 Jun · Shift 1 · Q14

Ionic Equilibrium question

2022 · 26 Jun · Shift 1 · Q14

JEE MainChemistryIonic EquilibriumNumerical+4 / −1
50 mL of 0.1 M CH3COOHCH_3COOHCH3​COOH is being titrated against 0.1 M NaOHNaOHNaOH. When 25 mL of NaOHNaOHNaOH has been added, the pH of the solution will be ‾×\underline{\hspace{2cm}}\times​× 10 −-− 2. (Nearest integer) (Given : pKa (CH3COOHCH_3COOHCH3​COOH) = 4.76) log 2 = 0.30 log 3 = 0.48 log 5 = 0.69 log 7 = 0.84 log 11 = 1.04
Numerical answer
PreviousNext

More from Ionic Equilibrium

  • At 310 K, the solubility of CaF2​ in water is 2.34×10−3 g/100 mL. The solubility product of CaF2​ is ​×10−8( mol/L)3…2022 · Numerical
  • In the titration of KMnO4​ and oxalic acid in acidic medium, the change in oxidation number of carbon at the end point is ​.2022 · Numerical
  • The plot of pH-metric titration of weak base NH4​OH vs strong acid HCl looks like :2022 · MCQ
  • pH value of 0.001 M NaOH solution is ​.2022 · Numerical
  • Ka​ for butyric acid (C3​H7​COOH) is 2×10−5. The pH of 0.2M solution of butyric acid is ​×10−1.…2022 · Numerical
  • Given below are two statements : One is labelled as Assertion A and the other is labelled as Reason R Assertion A : Permanganate titrations are not performed in presence of hydrochloric acid. Reason R : Chlorine is formed as a consequence…2022 · MCQ
  • The solubility product of a sparingly soluble salt A2​X3​ is 1.1 × 10 − 23. If specific conductance of the solution is 3 × 10 − 5 S m − 1, the limiting molar conductivity of the solution is x× 10 − 3 S m2…2022 · Numerical
  • A student needs to prepare a buffer solution of propanoic acid and its sodium salt with pH 4. The ratio of [CH3​CH2​COOH][CH3​CH2​COO−]​ required to make buffer is ​. Given : Ka​(CH3​CH2​COOH)=1.3×10−5…2022 · MCQ