Identify each named reaction and its typical product

We match each reaction in List-I with the product obtainable in List-II.

(A) Swarts reaction

Swarts reaction is used to prepare alkyl fluorides from alkyl chlorides/bromides using metallic fluorides.

$\text{R-Cl / R-Br} \xrightarrow{\text{AgF, SbF}_3, \text{etc.}} \text{R-F}$

Therefore, ethyl fluoride is obtained.

So, $A \to IV$

(B) Sandmeyer's reaction

In Sandmeyer reaction, an aryl diazonium salt reacts with cuprous salts to give substituted benzene derivatives.

For cyanation: $\text{C}_6\text{H}_5\text{N}_2^+Cl^- \xrightarrow{CuCN} \text{C}_6\text{H}_5\text{CN}$

Product is cyanobenzene.

So, $B \to III$

(C) Wurtz-Fittig reaction

Wurtz-Fittig reaction couples an aryl halide with an alkyl halide in presence of sodium in dry ether.

$\text{Ar-X} + \text{R-X} + 2Na \rightarrow \text{Ar-R} + 2NaX$

Example: $\text{C}_6\text{H}_5Br + \text{C}_2\text{H}_5Br + 2Na \rightarrow \text{C}_6\text{H}_5C_2\text{H}_5$

Product is ethyl benzene.

So, $C \to I$

(D) Finkelstein reaction

Finkelstein reaction is halogen exchange, generally converting alkyl chloride/bromide to alkyl iodide using sodium iodide in acetone.

$\text{R-Cl / R-Br} \xrightarrow{NaI/acetone} \text{R-I}$

Therefore, ethyl iodide is obtained.

So, $D \to II$

Final matching

$A-IV,\; B-III,\; C-I,\; D-II$

Compare with options

This corresponds to Option D.

Comparison with stored correct answer

Stored correct answer = D

Derived answer = D

Hence, they agree.