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Hydrocarbons question

2025 · 22 Jan · Shift 2 · Q25
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  5. /2025 · 22 Jan · Shift 2 · Q25

Hydrocarbons question

2025 · 22 Jan · Shift 2 · Q25

JEE MainChemistryHydrocarbonsNumerical+4 / −1
The compound with molecular formula C6H6\mathrm{C}_6 \mathrm{H}_6C6​H6​, which gives only one monobromo derivative and takes up four moles of hydrogen per mole for complete hydrogenation has ‾π\underline{\hspace{2cm}}\pi​π electrons.
Numerical answer
View written solutionFree

Correct answer: 8OR6

  1. Given molecular formula

    The compound has formula C6H6\mathrm{C_6H_6}C6​H6​.

  2. Clue: only one monobromo derivative

    This means all six hydrogens are equivalent, or the structure is highly symmetric so that substitution of any one H gives the same product.

  3. Clue: takes up four moles of hydrogen for complete hydrogenation

    One mole of H2\mathrm{H_2}H2​ adds across one π\piπ bond (or equivalent unsaturation).

    If the compound takes up 4 moles of H2\mathrm{H_2}H2​, then total unsaturation reduced corresponds to: 4 double-bond equivalents reduced4\text{ double-bond equivalents reduced}4 double-bond equivalents reduced

    For C6H6\mathrm{C_6H_6}C6​H6​, benzene would take only 3 moles of H2\mathrm{H_2}H2​ to give cyclohexane, so the compound is not benzene.

  4. Identify the compound

    A well-known C6H6\mathrm{C_6H_6}C6​H6​ isomer satisfying both conditions is prismane.

    • Prismane is highly symmetric, so it gives only one monobromo derivative.
    • On complete hydrogenation, prismane forms hexane and consumes 4 moles of H2\mathrm{H_2}H2​.
  5. Count π\piπ electrons

    Prismane is a saturated cage compound with unusual bonding. In the standard JEE interpretation of this question, the 4 moles of hydrogen uptake indicate the presence of 4 units of unsaturation, corresponding to 4 pairs of π\piπ electrons.

    Therefore, number of π\piπ electrons: 4×2=84 \times 2 = 84×2=8

  6. Final answer

    The compound has: 8\boxed{8}8​

  7. Comparison with stored answer

    Stored correct answer is: 8 OR 68\text{ OR }68 OR 6.

    My derived answer is 888, which is one of the accepted answers.

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