1. Identify the starting compound

   The given alkyne is: $\mathrm{CH_3-C\equiv CH}$ This is propyne.

2. First reaction: hydrogenation with $\mathrm{H_2/Pd-C}$

   Catalytic hydrogenation of an alkyne with $\mathrm{H_2/Pd-C}$ under controlled addition of one mole of hydrogen gives the corresponding alkene: $\mathrm{CH_3-C\equiv CH} \xrightarrow{H_2/Pd-C} \mathrm{CH_3-CH=CH_2}$

   So, $[A] = \mathrm{CH_3-CH=CH_2}$ which is propene.

3. Second reaction: ozonolysis of propene

   Now propene undergoes ozonolysis followed by reductive workup: $\mathrm{CH_3-CH=CH_2} \xrightarrow[(ii)\,Zn,H_2O]{(i)\,O_3}$

   Ozonolysis cleaves the double bond and converts each alkene carbon into a carbonyl group.

   Structure of propene: $\mathrm{CH_3-CH=CH_2}$

   Breaking the double bond:

   • The middle carbon gives ethanal $\mathrm{CH_3CHO}$
   • The terminal $\mathrm{CH_2}$ carbon gives methanal $\mathrm{HCHO}$

   Therefore, $[B] = \mathrm{CH_3CHO}$ $[C] = \mathrm{HCHO}$

4. Match with options

   This corresponds to:

   • $[A] = \mathrm{CH_3-CH=CH_2}$
   • $[B] = \mathrm{CH_3CHO}$
   • $[C] = \mathrm{HCHO}$

   Hence, the correct option is B.

5. Check other options briefly

   • A: gives ethanol as one ozonolysis product, which is impossible; ozonolysis gives carbonyl compounds, not alcohols.
   • C: takes $[A]$ as propane, but ozonolysis requires an alkene double bond.

Therefore, Option B is correct.