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Electrochemistry question

2021 · 26 Aug · Shift 2 · Q17

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2021 · 26 Aug · Shift 2 · Q17

Electrochemistry question

2021 · 26 Aug · Shift 2 · Q17

JEE MainChemistryElectrochemistryNumerical+4 / −1

For the galvanic cell, Zn(s) +

Cu^{2+}

(0.02 M)

\to

Zn^{2+}

(0.04 M) + Cu(s), Ecell =

\underline{\hspace{2cm}}

\times

10

-

2 V. (Nearest integer) [Use :

E_{Cu/C{u^{2 + }}}^0

=

-

0.34 V,

E_{Zn/Z{n^{2 + }}}^0

= + 0.76 V,

{{2.303RT} \over F} = 0.059\,V

]

Numerical answer

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