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Electrochemistry question

2021 · 25 Feb · Shift 2 · Q15

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JEE Main
Chemistry
Electrochemistry
2021 · 25 Feb · Shift 2 · Q15

Electrochemistry question

2021 · 25 Feb · Shift 2 · Q15

JEE MainChemistryElectrochemistryNumerical+4 / −1

Copper reduces NO

_3^ -

into

NO

and

NO_2

depending upon the concentration of

HNO_3

in solution. (Assuming fixed [Cu2+] and PNO = PNO2), the

HNO_3

concentration at which the thermodynamic tendency for reduction of NO

_3^ -

into

NO

and

NO_2

by copper is same is 10x M. The value of 2x is

\underline{\hspace{2cm}}

. (Rounded off to the nearest integer) [Given,

E_{C{u^{2 + }}/Cu}^o = 0.34

V,

E_{NO_3^ - /NO}^o = 0.96

V,

E_{NO_3^ - /N{O_2}}^o = 0.79

V and at 298 K,

{{RT} \over F}

(2.303) = 0.059]

Numerical answer

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