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Electrochemistry question

2021 · 24 Feb · Shift 1 · Q1
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  5. /2021 · 24 Feb · Shift 1 · Q1

Electrochemistry question

2021 · 24 Feb · Shift 1 · Q1

JEE MainChemistryElectrochemistryMCQ+4 / −1
The electrode potential of M2+M^{2+}M2+/M of 3d-series elements shows positive value for :
  1. A
    Zn
  2. B
    Fe
  3. C
    Cu
  4. D
    Co
View written solutionFree

Correct answer: C

  1. We are asked which 3d3d3d-series element has a positive standard electrode potential for the half-cell:

M2++2e−→MM^{2+} + 2e^- \rightarrow MM2++2e−→M

This means we need to identify the metal whose standard reduction potential E∘(M2+/M)E^\circ(M^{2+}/M)E∘(M2+/M) is positive.

  1. Recall the standard reduction potentials of the given metals:
  • For Zn2+/Zn\mathrm{Zn^{2+}/Zn}Zn2+/Zn: E∘=−0.76 VE^\circ = -0.76\,\text{V}E∘=−0.76V
  • For Fe2+/Fe\mathrm{Fe^{2+}/Fe}Fe2+/Fe: E∘=−0.44 VE^\circ = -0.44\,\text{V}E∘=−0.44V
  • For Co2+/Co\mathrm{Co^{2+}/Co}Co2+/Co: E∘=−0.28 VE^\circ = -0.28\,\text{V}E∘=−0.28V
  • For Cu2+/Cu\mathrm{Cu^{2+}/Cu}Cu2+/Cu: E∘=+0.34 VE^\circ = +0.34\,\text{V}E∘=+0.34V
  1. Now evaluate each option:
  • A: Zn →E∘<0\rightarrow E^\circ < 0→E∘<0 ❌
  • B: Fe →E∘<0\rightarrow E^\circ < 0→E∘<0 ❌
  • C: Cu →E∘>0\rightarrow E^\circ > 0→E∘>0 ✅
  • D: Co →E∘<0\rightarrow E^\circ < 0→E∘<0 ❌
  1. Therefore, the only metal among the given options with positive electrode potential is:

Cu\boxed{\text{Cu}}Cu​

So, the correct option is C.

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