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Electrochemistry question

2021 · 18 Mar · Shift 1 · Q23

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JEE Main
Chemistry
Electrochemistry
2021 · 18 Mar · Shift 1 · Q23

Electrochemistry question

2021 · 18 Mar · Shift 1 · Q23

JEE MainChemistryElectrochemistryNumerical+4 / −1

For the reaction 2

Fe^{3+}

(aq) + 2

I

-

(aq)

\to

2

Fe^{2+}

(aq) +

I_2

(s) the magnitude of the standard molar Gibbs free energy change,

\Delta

rG

_m^o

=

-

\underline{\hspace{2cm}}

kJ (Round off to the Nearest Integer).

\left[ {\begin{matrix} {E_{F{e^{2 + }}/Fe(s)}^o = - 0.440V;} & {E_{F{e^{3 + }}/Fe(s)}^o = - 0.036V} \\ {E_{{I_2}/2{I^ - }}^o = 0.539V;} & {F = 96500C} \\ \end{matrix} } \right]

Numerical answer

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