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Electrochemistry question

2014 · Shift 0 · Q23
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Electrochemistry question

2014 · Shift 0 · Q23

JEE MainChemistryElectrochemistryMCQ+4 / −1
The equivalent conductance of NaCl at concentration C and at infinite dilution are λC{\lambda _C}λC​ and λ∞{\lambda _\infty }λ∞​, respectively. The correct relationship between λC{\lambda _C}λC​ and λ∞{\lambda _\infty }λ∞​ is given as: (where the constant B is positive)
  1. A
    λC=λ∞+(B)C{\lambda _C} = {\lambda _\infty } + (B)CλC​=λ∞​+(B)C
  2. B
    λC=λ∞−(B)C{\lambda _C} = {\lambda _\infty } - (B)CλC​=λ∞​−(B)C
  3. C
    λC=λ∞−(B)C{\lambda _C} = {\lambda _\infty } - (B)\sqrt CλC​=λ∞​−(B)C​
  4. D
    λC=λ∞+(B)C{\lambda _C} = {\lambda _\infty } + (B)\sqrt CλC​=λ∞​+(B)C​
View written solutionFree

Correct answer: C

  1. Use Kohlrausch’s law for strong electrolytes

For a strong electrolyte like NaCl, the equivalent conductance (or molar/equivalent conductivity) decreases with concentration according to:

λC=λ∞−BC\lambda_C = \lambda_\infty - B\sqrt{C}λC​=λ∞​−BC​

where:

  • λC\lambda_CλC​ = equivalent conductance at concentration CCC
  • λ∞\lambda_\inftyλ∞​ = equivalent conductance at infinite dilution
  • B>0B > 0B>0 is a constant
  1. Reason for the negative sign

As concentration increases, inter-ionic interactions increase, which reduce the mobility of ions. Therefore conductance at finite concentration is less than conductance at infinite dilution:

λC<λ∞\lambda_C < \lambda_\inftyλC​<λ∞​

So the correction term must be subtracted, not added.

  1. Check dependence on concentration

For strong electrolytes, the decrease is proportional to C\sqrt{C}C​, not CCC.

Thus the correct relation is:

λC=λ∞−BC\lambda_C = \lambda_\infty - B\sqrt{C}λC​=λ∞​−BC​
  1. Evaluate options
  • A: λC=λ∞+BC\lambda_C = \lambda_\infty + BCλC​=λ∞​+BC ❌ wrong sign and wrong dependence
  • B: λC=λ∞−BC\lambda_C = \lambda_\infty - BCλC​=λ∞​−BC ❌ wrong dependence
  • C: λC=λ∞−BC\lambda_C = \lambda_\infty - B\sqrt{C}λC​=λ∞​−BC​ ✅ correct
  • D: λC=λ∞+BC\lambda_C = \lambda_\infty + B\sqrt{C}λC​=λ∞​+BC​ ❌ wrong sign

Therefore, the correct option is C.

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