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Electrochemistry question

2013 · Shift 0 · Q15

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JEE Main
Chemistry
Electrochemistry
2013 · Shift 0 · Q15

Electrochemistry question

2013 · Shift 0 · Q15

JEE MainChemistryElectrochemistryMCQ+4 / −1

Given

E_{C{r^{2 + }}/Cr}^o

= -0.74 V;

E_{MnO_4^ - /M{n^{2 + }}}^o

= 1.51 V

E_{C{r_2}O_7^{2 - }/C{r^{3 + }}}^o

= 1.33 V;

E_{Cl/C{l^ - }}^o

= 1.36 V Based on the data given above, strongest oxidising agent will be :

A
$Cr^{3+}$
B
$Mn^{2+}$
C
$MnO_4^ -$
D
$Cl^-$

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