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D and F Block Elements question

2023 · 6 Apr · Shift 1 · Q12
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D and F Block Elements question

2023 · 6 Apr · Shift 1 · Q12

JEE MainChemistryD and F Block ElementsMCQ+4 / −1
Strong reducing and oxidizing agents among the following, respectively, are :
  1. A
    Ce4+\mathrm{Ce}^{4+}Ce4+ and Eu2+\mathrm{Eu}^{2+}Eu2+
  2. B
    Eu2+\mathrm{Eu}^{2+}Eu2+ and Ce4+\mathrm{Ce}^{4+}Ce4+
  3. C
    Ce4+\mathrm{Ce}^{4+}Ce4+ and Tb4+\mathrm{Tb}^{4+}Tb4+
  4. D
    Ce3+\mathrm{Ce}^{3+}Ce3+ and Ce4+\mathrm{Ce}^{4+}Ce4+
View written solutionFree

Correct answer: B

  1. Identify what is being asked

We need the pair that represents:

  • strong reducing agent first
  • strong oxidizing agent second

So we must check which ion is most easily oxidized (thus acts as a reducing agent) and which ion is most easily reduced (thus acts as an oxidizing agent).


  1. Use standard lanthanide stability ideas

Among lanthanides, certain oxidation states are especially stable because of electronic configurations:

  • Ce4+\mathrm{Ce}^{4+}Ce4+ has configuration close to stable 4f04f^04f0
  • Eu2+\mathrm{Eu}^{2+}Eu2+ has especially stable half-filled configuration 4f74f^74f7
  • Tb4+\mathrm{Tb}^{4+}Tb4+ is less common but can exist

Now, chemical behavior:

(a) Ce4+\mathrm{Ce}^{4+}Ce4+

Ce4+\mathrm{Ce}^{4+}Ce4+ readily gains an electron to become Ce3+\mathrm{Ce}^{3+}Ce3+: Ce4++e−→Ce3+\mathrm{Ce}^{4+} + e^- \rightarrow \mathrm{Ce}^{3+}Ce4++e−→Ce3+ Since it gets reduced easily, it acts as a strong oxidizing agent.

(b) Eu2+\mathrm{Eu}^{2+}Eu2+

Eu2+\mathrm{Eu}^{2+}Eu2+ readily loses an electron to become Eu3+\mathrm{Eu}^{3+}Eu3+: Eu2+→Eu3++e−\mathrm{Eu}^{2+} \rightarrow \mathrm{Eu}^{3+} + e^-Eu2+→Eu3++e− Thus it acts as a strong reducing agent.

This is a standard result in lanthanide chemistry:

  • Eu2+\mathrm{Eu}^{2+}Eu2+ is a strong reducing agent.
  • Ce4+\mathrm{Ce}^{4+}Ce4+ is a strong oxidizing agent.

  1. Check each option

Option A: Ce4+\mathrm{Ce}^{4+}Ce4+ and Eu2+\mathrm{Eu}^{2+}Eu2+

This says:

  • reducing agent = Ce4+\mathrm{Ce}^{4+}Ce4+ ❌
  • oxidizing agent = Eu2+\mathrm{Eu}^{2+}Eu2+ ❌ Reversed.

Option B: Eu2+\mathrm{Eu}^{2+}Eu2+ and Ce4+\mathrm{Ce}^{4+}Ce4+

This says:

  • reducing agent = Eu2+\mathrm{Eu}^{2+}Eu2+ ✅
  • oxidizing agent = Ce4+\mathrm{Ce}^{4+}Ce4+ ✅ Correct.

Option C: Ce4+\mathrm{Ce}^{4+}Ce4+ and Tb4+\mathrm{Tb}^{4+}Tb4+

Ce4+\mathrm{Ce}^{4+}Ce4+ is not the strong reducing agent, so this is incorrect. ❌

Option D: Ce3+\mathrm{Ce}^{3+}Ce3+ and Ce4+\mathrm{Ce}^{4+}Ce4+

Ce4+\mathrm{Ce}^{4+}Ce4+ is a strong oxidizing agent, but Ce3+\mathrm{Ce}^{3+}Ce3+ is not the strongest reducing agent among these. ❌


  1. Final conclusion

The strong reducing and oxidizing agents respectively are: Eu2+ and Ce4+\boxed{\mathrm{Eu}^{2+} \text{ and } \mathrm{Ce}^{4+}}Eu2+ and Ce4+​ So the correct option is B.


  1. Comparison with stored answer

Stored correct answer: B

Our derived answer: B

They agree.

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