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D and F Block Elements question

2021 · 22 Jul · Shift 2 · Q21
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D and F Block Elements question

2021 · 22 Jul · Shift 2 · Q21

JEE MainChemistryD and F Block ElementsNumerical+4 / −1
Number of electrons that Vanadium (Z = 23) has in p-orbitals is equal to ‾\underline{\hspace{2cm}}​
Numerical answer
View written solutionFree

Correct answer: 12

  1. Write the electronic configuration of Vanadium

Vanadium has atomic number Z=23Z = 23Z=23, so it has 232323 electrons.

Its ground-state electronic configuration is:

1s2 2s2 2p6 3s2 3p6 3d3 4s21s^2\,2s^2\,2p^6\,3s^2\,3p^6\,3d^3\,4s^21s22s22p63s23p63d34s2
  1. Identify electrons present in all p-orbitals

The occupied p-subshells are:

  • 2p62p^62p6
  • 3p63p^63p6

There is no electron in 4p4p4p for vanadium.

  1. Count total p-electrons
2p6+3p6=6+6=122p^6 + 3p^6 = 6 + 6 = 122p6+3p6=6+6=12
  1. Final answer

Therefore, the number of electrons in p-orbitals in vanadium is:

12\boxed{12}12​
  1. Comparison with stored correct answer

Stored correct answer = 121212

My derived answer also = 121212, so they agree.

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