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D and F Block Elements question

2019 · 9 Apr · Shift 2 · Q3
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D and F Block Elements question

2019 · 9 Apr · Shift 2 · Q3

JEE MainChemistryD and F Block ElementsMCQ+4 / −1
The maximum number of possible oxidation states of actinoides are shown by :
  1. A
    nobelium (No) and lawrencium (Lr)
  2. B
    actinium (Ac) and thorium (Th)
  3. C
    neptunium (Np) and plutonium (Pu)
  4. D
    berkelium (Bk) and californium (Cf)
View written solutionFree

Correct answer: C

  1. Key idea: In actinoids, many oxidation states are possible because the energies of the 5f5f5f, 6d6d6d, and 7s7s7s orbitals are quite close.

  2. We need the pair of elements that show the maximum number of oxidation states.

  3. Recall the common trend in actinoids:

    • Early actinoids show a larger variety of oxidation states.
    • The highest variability is seen around neptunium and plutonium.
  4. Typical oxidation states:

    • Ac, Th: limited oxidation states, mainly +3+3+3 and +4+4+4 respectively.
    • No, Lr: mostly stable in +2/+3+2/+3+2/+3 or +3+3+3 states; not many variable oxidation states.
    • Bk, Cf: mostly +3+3+3, with a few others like +4+4+4 possible in some cases, but still limited.
    • Np, Pu: show a wide range such as +3,+4,+5,+6,+3, +4, +5, +6,+3,+4,+5,+6, and +7+7+7.
  5. Therefore, the actinoids with the maximum number of possible oxidation states are: Np and Pu\boxed{\text{Np and Pu}}Np and Pu​

  6. Hence, the correct option is C.

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