Key idea: Nitric acid is an oxidizing acid, so with metals like zinc, hydrogen gas is generally not evolved. Instead, nitric acid is reduced to different nitrogen oxides depending on its concentration.

Reaction with dilute nitric acid: For zinc, with dilute $HNO_3$, the reduction product is typically nitrous oxide $N_2O$.

A representative reaction is: $4Zn + 10HNO_3(\text{dil.}) \rightarrow 4Zn(NO_3)_2 + N_2O + 5H_2O$

So, with dilute nitric acid, zinc produces: $N_2O$

Reaction with concentrated nitric acid: With concentrated $HNO_3$, nitric acid is reduced mainly to nitrogen dioxide $NO_2$.

A representative reaction is: $Zn + 4HNO_3(\text{conc.}) \rightarrow Zn(NO_3)_2 + 2NO_2 + 2H_2O$

So, with concentrated nitric acid, zinc produces: $NO_2$

Match with the options: The question asks for products with dilute and concentrated nitric acid, respectively:

• Dilute $HNO_3 \rightarrow N_2O$
• Concentrated $HNO_3 \rightarrow NO_2$

Therefore the correct option is: $\boxed{\text{D: } N_2O \text{ and } NO_2}$

Comparison with stored answer: Stored correct answer = D

Our derived answer = D

Hence, they agree.