- A(III) > (I) > (II) > (IV)
- B(II) (I) > (IV) > (III)
- C(III) > (I) > (IV) > (II)
- D(I) > (IV) > (III) > (II)
View written solutionFree
Correct answer: D
- Find oxidation state and d-electron count for each complex
The spin-only magnetic moment is where is the number of unpaired electrons. So we first determine for each complex.
- Complex (I):
Since are counter ions, the complex cation is .
- Oxidation state of
is a weak field ligand, so octahedral high-spin configuration:
Number of unpaired electrons:
Thus,
- Complex (II):
The complex ion is .
Let oxidation state of Fe be :
So is .
is a strong field ligand, so octahedral low-spin:
Number of unpaired electrons:
Thus,
- Complex (III): with
The complex ion is .
Each oxalate ligand has charge . Let oxidation state of Fe be :
So is .
Given , it is low spin octahedral:
Number of unpaired electrons:
Thus,
- Complex (IV):
The complex ion is .
Let oxidation state of Co be :
So is .
is a weak field ligand, and tetrahedral complexes are generally high spin.
For tetrahedral high spin, number of unpaired electrons:
Thus,
- Compare magnetic moments
- (I): ,
- (IV): ,
- (III): ,
- (II): ,
Therefore,
- Match with options
This corresponds to Option D.
- Comparison with stored correct answer
Stored correct answer: D
Our derived answer: D
So the derived answer agrees with the stored answer.
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