
- A8 and 6
- B8 and 8
- C6 and 8
- D6 and 6
View written solutionFree
Correct answer: C
-
Interpret the question
We need the maximum possible denticity of the given ligand toward:
- a common transition metal ion, and
- an inner-transition metal ion.
The ligand referred to here is the well-known aminopolycarboxylate ligand that can potentially bind through:
- 2 nitrogen donor atoms, and
- 6 oxygen donor atoms from carboxylate groups.
So, the ligand has a total of possible donor atoms.
-
For a common transition metal ion
Common transition metal ions usually prefer coordination number up to 6 in stable complexes.
Therefore, even if the ligand has 8 donor atoms available, toward a common transition metal ion it can at most behave as a:
-
For an inner-transition metal ion
Inner-transition metal ions (especially lanthanoids/actinoids) are larger in size and can accommodate higher coordination numbers, often 8 or more.
Hence, this ligand can use all its 8 donor atoms and act as:
-
Match with options
Thus, the maximum possible denticities are:
- toward a common transition metal ion: 6
- toward an inner-transition metal ion: 8
So the correct option is:
-
Comparison with stored correct answer
Stored correct answer = C.
Our derived answer = C.
Hence, they agree.
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