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Coordination Compounds question

2019 · 9 Apr · Shift 2 · Q13
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Coordination Compounds question

2019 · 9 Apr · Shift 2 · Q13

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
The maximum possible denticities of a ligand given below towards a common transition and inner-transition metal ion, respectively, are : JEE Main 2019 (Online) 9th April Evening Slot Chemistry - Coordination Compounds Question 249 English
  1. A
    8 and 6
  2. B
    8 and 8
  3. C
    6 and 8
  4. D
    6 and 6
View written solutionFree

Correct answer: C

  1. Interpret the question

    We need the maximum possible denticity of the given ligand toward:

    • a common transition metal ion, and
    • an inner-transition metal ion.

    The ligand referred to here is the well-known aminopolycarboxylate ligand that can potentially bind through:

    • 2 nitrogen donor atoms, and
    • 6 oxygen donor atoms from carboxylate groups.

    So, the ligand has a total of 2+6=82 + 6 = 82+6=8 possible donor atoms.

  2. For a common transition metal ion

    Common transition metal ions usually prefer coordination number up to 6 in stable complexes.

    Therefore, even if the ligand has 8 donor atoms available, toward a common transition metal ion it can at most behave as a: 6-dentate ligand\boxed{6\text{-dentate ligand}}6-dentate ligand​

  3. For an inner-transition metal ion

    Inner-transition metal ions (especially lanthanoids/actinoids) are larger in size and can accommodate higher coordination numbers, often 8 or more.

    Hence, this ligand can use all its 8 donor atoms and act as: 8-dentate ligand\boxed{8\text{-dentate ligand}}8-dentate ligand​

  4. Match with options

    Thus, the maximum possible denticities are:

    • toward a common transition metal ion: 6
    • toward an inner-transition metal ion: 8

    So the correct option is: C: 6 and 8\boxed{\text{C: }6\text{ and }8}C: 6 and 8​

  5. Comparison with stored correct answer

    Stored correct answer = C.

    Our derived answer = C.

    Hence, they agree.

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