JEE MainChemistryCoordination CompoundsMCQ+4 / −1
The isomer(s) of that has/have a –– angle of 90°, is/are :
- Acis only
- Bcis and trans
- Cmeridional and trans
- Dtrans only
View written solutionFree
Correct answer: A
- Identify the complex and its geometry
The complex is
Since the coordination number is , the geometry is octahedral.
So the two possible geometrical isomers are:
- cis
- trans
There is no possibility of meridional here, because mer/fac terminology applies to complexes of type , not .
- Understand the meaning of –– angle
This is the angle between the two bonds in the octahedral complex.
In an octahedral geometry:
- adjacent positions make an angle of
- opposite positions make an angle of
- Check the cis isomer
In the cis isomer, the two ligands are adjacent to each other.
Therefore,
So cis satisfies the condition.
- Check the trans isomer
In the trans isomer, the two ligands are opposite to each other.
Therefore,
So trans does not satisfy the condition.
- Evaluate the options
- A: cis only → Correct
- B: cis and trans → Incorrect
- C: meridional and trans → Incorrect, meridional not applicable here
- D: trans only → Incorrect
- Final answer
The isomer having –– angle equal to is:
So the correct option is A.
- Comparison with stored correct answer
Stored correct answer: A
My derived answer: A
They agree.
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