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Chemical Equilibrium question

2024 · 29 Jan · Shift 2 · Q24

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JEE Main
Chemistry
Chemical Equilibrium
2024 · 29 Jan · Shift 2 · Q24

Chemical Equilibrium question

2024 · 29 Jan · Shift 2 · Q24

JEE MainChemistryChemical EquilibriumNumerical+4 / −1

The following concentrations were observed at

500 \mathrm{~K}

for the formation of

\mathrm{NH}_3

from

\mathrm{N}_2

and

\mathrm{H}_2

. At equilibrium ;

\left[\mathrm{N}_2\right]=2 \times 10^{-2} \mathrm{M},\left[\mathrm{H}_2\right]=3 \times 10^{-2} \mathrm{M}

and

\left[\mathrm{NH}_3\right]=1.5 \times 10^{-2} \mathrm{M}

. Equilibrium constant for the reaction is

\underline{\hspace{2cm}}

.

Numerical answer

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